16x^2-8x-288=0

Solution for 16x^2-8x-288=0 equation:

16x^2-8x-288=0

a = 16; b = -8; c = -288;
Δ = b2-4ac
Δ = -82-4·16·(-288)
Δ = 18496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{18496}=136$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-136}{2*16}=\frac{-128}{32}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+136}{2*16}=\frac{144}{32}
=4+1/2
$